What is the answer to 2^{3k-1}*2^{5k-7}=16 ?

The answer to 2^{3k-1}*2^{5k-7}=16 is k= 3/2

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2^{3k-1}*2^{5k-7}=16

2^{3 k - 1} \cdot 2^{5 k - 7} = 16

k = \frac{3}{2}

Decimal Notation

k = 1.5

Solution steps

2^{3 k - 1} \cdot 2^{5 k - 7} = 16

Apply exponent rules

8 k - 8 = 4

Solve

8 k - 8 = 4 : k = \frac{3}{2}

k = \frac{3}{2}

4^{2 x} = 62 5^{3 x + 5}

\frac{1}{2} = 1 - e^{- 2 x}

7^{x - 1} = 49

7 \cdot 9^{x} - 2 \cdot 3^{2 x + 1} = 90 - 3^{x}

7^{9 x - 2} = 1 0^{2 x - 2}

What is the answer to 2^{3k-1}*2^{5k-7}=16 ?
The answer to 2^{3k-1}*2^{5k-7}=16 is k= 3/2
Solve for k: 2^{3k-1}*2^{5k-7}=16
The solution is k= 3/2