What is the answer to 3^{x+5}=17^x ?

The answer to 3^{x+5}=17^x is x=(5ln(3))/(ln(17)-ln(3))

Solve for x: 3^{x+5}=17^x

The solution is x=(5ln(3))/(ln(17)-ln(3))

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3^{x + 5} = 1 7^{x}

x = \frac{5 ln ( 3 )}{ln ( 17 ) - ln ( 3 )}

Decimal Notation

x = 3.16675 \dots

Solution steps

3^{x + 5} = 1 7^{x}

Apply exponent rules

(x + 5) ln (3) = x ln (17)

Solve

(x + 5) ln (3) = x ln (17) : x = \frac{5 ln ( 3 )}{ln ( 17 ) - ln ( 3 )}

x = \frac{5 ln ( 3 )}{ln ( 17 ) - ln ( 3 )}

- e^{- x} + 6 e^{- 6 x} = 0

2^{3 x} = 1 6^{1 - x}

5 \cdot 1 0^{2 x} = 1

4^{2 x + 7} = 3 2^{2 x - 3}

(5^{x})^{- 1} = 25

What is the answer to 3^{x+5}=17^x ?
The answer to 3^{x+5}=17^x is x=(5ln(3))/(ln(17)-ln(3))
Solve for x: 3^{x+5}=17^x
The solution is x=(5ln(3))/(ln(17)-ln(3))