What is the answer to 6^{x+1}=13^x ?

The answer to 6^{x+1}=13^x is x=(ln(6))/(ln(13)-ln(6))

Solve for x: 6^{x+1}=13^x

The solution is x=(ln(6))/(ln(13)-ln(6))

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6^{x + 1} = 1 3^{x}

x = \frac{ln ( 6 )}{ln ( 13 ) - ln ( 6 )}

Decimal Notation

x = 2.31736 \dots

Solution steps

6^{x + 1} = 1 3^{x}

Apply exponent rules

(x + 1) ln (6) = x ln (13)

Solve

(x + 1) ln (6) = x ln (13) : x = \frac{ln ( 6 )}{ln ( 13 ) - ln ( 6 )}

x = \frac{ln ( 6 )}{ln ( 13 ) - ln ( 6 )}

5^{x + 1} + 5^{x} + 5^{x - 1} = 31

2^{x + 2} + 5 \times 2^{x - 1} = \frac{13}{16}

4 e^{3 - x} = 3^{2 x + 5}

5^{n} = 125

- e^{- x} - 1 = 0

What is the answer to 6^{x+1}=13^x ?
The answer to 6^{x+1}=13^x is x=(ln(6))/(ln(13)-ln(6))
Solve for x: 6^{x+1}=13^x
The solution is x=(ln(6))/(ln(13)-ln(6))