What is the answer to 10^x=49 ?

The answer to 10^x=49 is x=(2ln(7))/(ln(10))

The solution is x=(2ln(7))/(ln(10))

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10^x=49

1 0^{x} = 49

x = \frac{2 ln ( 7 )}{ln ( 10 )}

Decimal Notation

x = 1.69019 \dots

Solution steps

1 0^{x} = 49

Apply exponent rules

x ln (10) = ln (49)

Solve

x ln (10) = ln (49) : x = \frac{2 ln ( 7 )}{ln ( 10 )}

x = \frac{2 ln ( 7 )}{ln ( 10 )}

(\frac{1}{2})^{x^{2}} = 3^{x}

1 6^{x^{2} + 1} = 2^{4 x + 7}

5^{2 x - 1} - 5^{2 x - 3} = 4.8

7 e^{7 x} - e^{- x} = 0

x e^{- x} - 2 e^{- x} = 0