What is the answer to 7^{2+x}= 1/(49^{x+3)} ?

The answer to 7^{2+x}= 1/(49^{x+3)} is x=-8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{2+x}= 1/(49^{x+3)}

7^{2 + x} = \frac{1}{4 9 ^{x + 3}}

x = - \frac{8}{3}

Decimal Notation

x = - 2.66666 \dots

Solution steps

7^{2 + x} = \frac{1}{4 9 ^{x + 3}}

Apply exponent rules

2 + x = 2 (- x - 3)

Solve

2 + x = 2 (- x - 3) : x = - \frac{8}{3}

x = - \frac{8}{3}

Verify Solutions:

x = - \frac{8}{3}

True

The solution is

x = - \frac{8}{3}

3^{x} = 53

3^{x} = 38

1 6^{3 x} = 8^{x + 6}

(\frac{4}{9})^{x} = \frac{81}{16}

(\frac{1}{8})^{x} = 64

What is the answer to 7^{2+x}= 1/(49^{x+3)} ?
The answer to 7^{2+x}= 1/(49^{x+3)} is x=-8/3
Solve for x: 7^{2+x}= 1/(49^{x+3)}
The solution is x=-8/3