What is the answer to (4/9)^x= 81/16 ?

The answer to (4/9)^x= 81/16 is x=(ln(81/16))/(ln(4/9))

Solve for x: (4/9)^x= 81/16

The solution is x=(ln(81/16))/(ln(4/9))

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(\frac{4}{9})^{x} = \frac{81}{16}

x = \frac{ln ( \frac{81}{16} )}{ln ( \frac{4}{9} )}

Decimal

x = - 2

Solution steps

(\frac{4}{9})^{x} = \frac{81}{16}

Apply exponent rules

x ln (\frac{4}{9}) = ln (\frac{81}{16})

Solve

x ln (\frac{4}{9}) = ln (\frac{81}{16}) : x = \frac{ln ( \frac{81}{16} )}{ln ( \frac{4}{9} )}

x = \frac{ln ( \frac{81}{16} )}{ln ( \frac{4}{9} )}

(\frac{1}{8})^{x} = 64

5^{3 n} = 125

10 0^{x} = 0.1

1 6^{2 x + 4} = 8^{2 x}

3^{2 x} - 4 (3^{x}) + 3 = 0

What is the answer to (4/9)^x= 81/16 ?
The answer to (4/9)^x= 81/16 is x=(ln(81/16))/(ln(4/9))
Solve for x: (4/9)^x= 81/16
The solution is x=(ln(81/16))/(ln(4/9))