What is the answer to 5^{x+2}=7^x ?

The answer to 5^{x+2}=7^x is x=(2ln(5))/(ln(7)-ln(5))

Solve for x: 5^{x+2}=7^x

The solution is x=(2ln(5))/(ln(7)-ln(5))

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5^{x + 2} = 7^{x}

x = \frac{2 ln ( 5 )}{ln ( 7 ) - ln ( 5 )}

Decimal Notation

x = 9.56654 \dots

Solution steps

5^{x + 2} = 7^{x}

Apply exponent rules

(x + 2) ln (5) = x ln (7)

Solve

(x + 2) ln (5) = x ln (7) : x = \frac{2 ln ( 5 )}{ln ( 7 ) - ln ( 5 )}

x = \frac{2 ln ( 5 )}{ln ( 7 ) - ln ( 5 )}

3^{4 x - 4} = 81

4^{x} = 4096

8^{0.4 x} = 5

x, 8 1^{4 x + 4} = 3^{x^{2} + 10 x - 11}

4 9^{x + 1} = (\frac{1}{7})^{x}

What is the answer to 5^{x+2}=7^x ?
The answer to 5^{x+2}=7^x is x=(2ln(5))/(ln(7)-ln(5))
Solve for x: 5^{x+2}=7^x
The solution is x=(2ln(5))/(ln(7)-ln(5))