What is the answer to 9^{2x}-3*9^x+2=0 ?

The answer to 9^{2x}-3*9^x+2=0 is x=(ln(2))/(2ln(3)),x=0

Solve for x: 9^{2x}-3*9^x+2=0

The solution is x=(ln(2))/(2ln(3)),x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^{2 x} - 3 \cdot 9^{x} + 2 = 0

x = \frac{ln ( 2 )}{2 ln ( 3 )}, x = 0

Decimal Notation

x = 0.31546 \dots, x = 0

Solution steps

9^{2 x} - 3 \cdot 9^{x} + 2 = 0

Apply exponent rules

(9^{x})^{2} - 3 \cdot 9^{x} + 2 = 0

Rewrite the equation with

9^{x} = u

(u)^{2} - 3 u + 2 = 0

Solve

u^{2} - 3 u + 2 = 0 : u = 2, u = 1

u = 2, u = 1

Substitute back

u = 9^{x},

solve for

x

Solve

9^{x} = 2 : x = \frac{ln ( 2 )}{2 ln ( 3 )}

Solve

9^{x} = 1 : x = 0

x = \frac{ln ( 2 )}{2 ln ( 3 )}, x = 0

6 4^{2 x} = 1 6^{x + 1}

x \times e^{x} = 0

lo g_{2} (4^{x + 4}) = - 2

x^{l o g_{10} (x)} = 10

2 e^{2 x} + e^{x} = 6

What is the answer to 9^{2x}-3*9^x+2=0 ?
The answer to 9^{2x}-3*9^x+2=0 is x=(ln(2))/(2ln(3)),x=0
Solve for x: 9^{2x}-3*9^x+2=0
The solution is x=(ln(2))/(2ln(3)),x=0