What is the answer to 4^{x-x^2}= 1/(64^x) ?

The answer to 4^{x-x^2}= 1/(64^x) is x=0,x=4

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4^{x-x^2}= 1/(64^x)

4^{x - x^{2}} = \frac{1}{6 4 ^{x}}

x = 0, x = 4

Solution steps

4^{x - x^{2}} = \frac{1}{6 4 ^{x}}

Apply exponent rules

x - x^{2} = - 3 x

Solve

x - x^{2} = - 3 x : x = 0, x = 4

x = 0, x = 4

Verify Solutions:

x = 0

True

, x = 4

True

The solutions are

x = 0, x = 4

x, \frac{e ^{2 x + 1}}{5} = yz

15 e^{5 x} = 5

62 \cdot 1 0^{x} = 40

7 e^{3 n - 5} + 5 = - 89

x^{2 x} = (2 x)^{x}

What is the answer to 4^{x-x^2}= 1/(64^x) ?
The answer to 4^{x-x^2}= 1/(64^x) is x=0,x=4
Solve for x: 4^{x-x^2}= 1/(64^x)
The solution is x=0,x=4