What is the answer to 5\times 4^{4x-5}=85 ?

The answer to 5\times 4^{4x-5}=85 is x=(ln(17)+10ln(2))/(8ln(2))

Solve for x: 5\times 4^{4x-5}=85

The solution is x=(ln(17)+10ln(2))/(8ln(2))

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5 \cdot 4^{4 x - 5} = 85

x = \frac{ln ( 17 ) + 10 ln ( 2 )}{8 ln ( 2 )}

Decimal Notation

x = 1.76093 \dots

Solution steps

5 \cdot 4^{4 x - 5} = 85

Divide both sides by

5

4^{4 x - 5} = 17

Apply exponent rules

(4 x - 5) ln (4) = ln (17)

Solve

(4 x - 5) ln (4) = ln (17) : x = \frac{ln ( 17 ) + 10 ln ( 2 )}{8 ln ( 2 )}

x = \frac{ln ( 17 ) + 10 ln ( 2 )}{8 ln ( 2 )}

4^{x + 2} = 6 4^{x}

6^{x^{3}} = 21 6^{x}

3^{l o g_{27} (3 x - 2)} = 7

e^{x^{2}} = e^{16 x} \cdot \frac{1}{e ^{63}}

5^{x} = 9^{x}

What is the answer to 5\times 4^{4x-5}=85 ?
The answer to 5\times 4^{4x-5}=85 is x=(ln(17)+10ln(2))/(8ln(2))
Solve for x: 5\times 4^{4x-5}=85
The solution is x=(ln(17)+10ln(2))/(8ln(2))