What is the answer to 3^{log_{27}(3x-2)}=7 ?

The answer to 3^{log_{27}(3x-2)}=7 is x=(27^{(ln(7))/(ln(3))}+2)/3

Solve for x: 3^{log_{27}(3x-2)}=7

The solution is x=(27^{(ln(7))/(ln(3))}+2)/3

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3^{l o g_{27} (3 x - 2)} = 7

x = \frac{2 7 ^{\frac{l n ( 7 )}{l n ( 3 )}} + 2}{3}

Decimal Notation

x = 115

Solution steps

3^{l o g_{27} (3 x - 2)} = 7

Apply exponent rules

lo g_{27} (3 x - 2) ln (3) = ln (7)

Solve

lo g_{27} (3 x - 2) ln (3) = ln (7) : x = \frac{2 7 ^{\frac{l n ( 7 )}{l n ( 3 )}} + 2}{3}

x = \frac{2 7 ^{\frac{l n ( 7 )}{l n ( 3 )}} + 2}{3}

e^{x^{2}} = e^{16 x} \cdot \frac{1}{e ^{63}}

5^{x} = 9^{x}

2 5^{x} + 5^{1 + 2 x} = 50

- 4 e^{- 4 x} = \frac{e ^{- 12} - 1}{3}

5^{x - 4} = 25

What is the answer to 3^{log_{27}(3x-2)}=7 ?
The answer to 3^{log_{27}(3x-2)}=7 is x=(27^{(ln(7))/(ln(3))}+2)/3
Solve for x: 3^{log_{27}(3x-2)}=7
The solution is x=(27^{(ln(7))/(ln(3))}+2)/3