What is the answer to solvefor y,e^{xy}+ln(x)=10 ?

The answer to solvefor y,e^{xy}+ln(x)=10 is y=(ln(10-ln(x)))/x

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solvefor y,e^{xy}+ln(x)=10

solve for

y, e^{x y} + ln (x) = 10

y = \frac{ln ( 10 - ln ( x ) )}{x}

Solution steps

e^{x y} + ln (x) = 10

Move

ln (x)

to the right side

e^{x y} = 10 - ln (x)

Apply exponent rules

x y = ln (10 - ln (x))

Solve

x y = ln (10 - ln (x)) : y = \frac{ln ( 10 - ln ( x ) )}{x}

y = \frac{ln ( 10 - ln ( x ) )}{x}

3^{x} \times 5^{2 x} = 150

4^{x + 2} - 4^{x} = 120

15 - e^{x - 8} = 4

What is the answer to solvefor y,e^{xy}+ln(x)=10 ?
The answer to solvefor y,e^{xy}+ln(x)=10 is y=(ln(10-ln(x)))/x