Solution
Solution
+1
Decimal Notation
Solution steps
Apply exponent rules
Solve
Popular Examples
4^x+4^{x+1}=20*42*\sqrt[5]{27}= 6/(sqrt(3^x))(2^{2x+3})/(2^{3x-1)}=644^{sqrt(x+1)}=64*2^{sqrt(x+1)}\sqrt[3]{2\sqrt[3]{2\sqrt[3]{2}}}=2^x
Frequently Asked Questions (FAQ)
What is the answer to 9^{x-5}=12^x ?
The answer to 9^{x-5}=12^x is x=(10ln(3))/(ln(3/4))Solve for x: 9^{x-5}=12^x
The solution is x=(10ln(3))/(ln(3/4))