What is the answer to 2*\sqrt[5]{27}= 6/(sqrt(3^x)) ?

The answer to 2*\sqrt[5]{27}= 6/(sqrt(3^x)) is x= 4/5

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2*\sqrt[5]{27}= 6/(sqrt(3^x))

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

Multiply both sides by

3^{x}

Simplify

Apply exponent rules

x \frac{1}{2} = \frac{2}{5}

Solve

x \frac{1}{2} = \frac{2}{5} : x = \frac{4}{5}

x = \frac{4}{5}

Verify Solutions:

x = \frac{4}{5}

True

The solution is

x = \frac{4}{5}

\frac{2 ^{2 x + 3}}{2 ^{3 x - 1}} = 64

4^{x + 1} = 64 \cdot 2^{x + 1}

\frac{3 ^{2 x + 5}}{9} = 3^{x + 1}

1 7^{X + 8} = 1 7^{10}

What is the answer to 2*\sqrt[5]{27}= 6/(sqrt(3^x)) ?
The answer to 2*\sqrt[5]{27}= 6/(sqrt(3^x)) is x= 4/5
Solve for x: 2*\sqrt[5]{27}= 6/(sqrt(3^x))
The solution is x= 4/5