What is the answer to (3^{2x+5})/9 =3^{x+1} ?

The answer to (3^{2x+5})/9 =3^{x+1} is x=-2

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(3^{2x+5})/9 =3^{x+1}

\frac{3 ^{2 x + 5}}{9} = 3^{x + 1}

x = - 2

Solution steps

\frac{3 ^{2 x + 5}}{9} = 3^{x + 1}

Multiply both sides by

9

\frac{3 ^{2 x + 5}}{9} \cdot 9 = 3^{x + 1} \cdot 9

Simplify

3^{2 x + 5} = 3^{x + 1} \cdot 9

Apply exponent rules

2 x + 5 = x + 3

Solve

2 x + 5 = x + 3 : x = - 2

x = - 2

1 7^{X + 8} = 1 7^{10}

26214 4^{4 x + 6} = 409 6^{- x - 15}

16 = 1 0^{2 + 3 x}

7^{2 + x} = 1.4 \cdot 5^{2 + x}

9 \times 8 1^{1 - 2 x} = 2 7^{2 - x}

What is the answer to (3^{2x+5})/9 =3^{x+1} ?
The answer to (3^{2x+5})/9 =3^{x+1} is x=-2
Solve for x: (3^{2x+5})/9 =3^{x+1}
The solution is x=-2