What is the answer to 9\times 81^{1-2x}=27^{2-x} ?

The answer to 9\times 81^{1-2x}=27^{2-x} is x=0

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9\times 81^{1-2x}=27^{2-x}

9 \cdot 8 1^{1 - 2 x} = 2 7^{2 - x}

x = 0

Solution steps

9 \cdot 8 1^{1 - 2 x} = 2 7^{2 - x}

Apply exponent rules

4 (1 - 2 x) + 2 = 3 (2 - x)

Solve

4 (1 - 2 x) + 2 = 3 (2 - x) : x = 0

x = 0

1 0^{x} = 121

x^{2} e^{x} + 2 x e^{x} = 0

6^{- 2 x} = 6^{3}

3 8^{x} = 65536

e^{x + 1} = 2^{x}

What is the answer to 9\times 81^{1-2x}=27^{2-x} ?
The answer to 9\times 81^{1-2x}=27^{2-x} is x=0
Solve for x: 9\times 81^{1-2x}=27^{2-x}
The solution is x=0