What is the answer to 17/327 =e^{-9.22\times 10^{-4t}} ?

The answer to 17/327 =e^{-9.22\times 10^{-4t}} is t=-(ln(-\frac{ln(17/327))/(9.22))}{4ln(10)}

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17/327 =e^{-9.22\times 10^{-4t}}

\frac{17}{327} = e^{- 9.22 \cdot 1 0^{- 4 t}}

t = - \frac{ln ( - \frac{l n ( \frac{17}{327} )}{9.22} )}{4 ln ( 10 )}

Decimal Notation

t = 0.12347 \dots

Solution steps

\frac{17}{327} = e^{- 9.22 \cdot 1 0^{- 4 t}}

Apply exponent rules

- 4 t ln (10) = ln (- \frac{ln ( \frac{17}{327} )}{9.22})

Solve

- 4 t ln (10) = ln (- \frac{ln ( \frac{17}{327} )}{9.22}) : t = - \frac{ln ( - \frac{l n ( \frac{17}{327} )}{9.22} )}{4 ln ( 10 )}

t = - \frac{ln ( - \frac{l n ( \frac{17}{327} )}{9.22} )}{4 ln ( 10 )}

7^{3 x + 4} = 4 9^{2 x + 1}

y, (3^{3})^{- 1} = x^{y}

e^{x + 9} = \frac{1}{e}

3^{x + 2} + 10 = 9^{x}

e^{x^{2}} = e^{17 x} \cdot \frac{1}{e ^{70}}

What is the answer to 17/327 =e^{-9.22\times 10^{-4t}} ?
The answer to 17/327 =e^{-9.22\times 10^{-4t}} is t=-(ln(-\frac{ln(17/327))/(9.22))}{4ln(10)}