What is the answer to 7^{3x+4}=49^{2x+1} ?

The answer to 7^{3x+4}=49^{2x+1} is x=2

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7^{3x+4}=49^{2x+1}

7^{3 x + 4} = 4 9^{2 x + 1}

x = 2

Solution steps

7^{3 x + 4} = 4 9^{2 x + 1}

Apply exponent rules

3 x + 4 = 2 (2 x + 1)

Solve

3 x + 4 = 2 (2 x + 1) : x = 2

x = 2

y, (3^{3})^{- 1} = x^{y}

e^{x + 9} = \frac{1}{e}

3^{x + 2} + 10 = 9^{x}

e^{x^{2}} = e^{17 x} \cdot \frac{1}{e ^{70}}

4^{2 x + 1} = 3^{x + 5}

What is the answer to 7^{3x+4}=49^{2x+1} ?
The answer to 7^{3x+4}=49^{2x+1} is x=2
Solve for x: 7^{3x+4}=49^{2x+1}
The solution is x=2