What is the answer to 3^{2x}-28\times 3^x+27=0 ?

The answer to 3^{2x}-28\times 3^x+27=0 is x=3,x=0

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3^{2x}-28\times 3^x+27=0

3^{2 x} - 28 \cdot 3^{x} + 27 = 0

x = 3, x = 0

Solution steps

3^{2 x} - 28 \cdot 3^{x} + 27 = 0

Apply exponent rules

(3^{x})^{2} - 28 \cdot 3^{x} + 27 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} - 28 u + 27 = 0

Solve

u^{2} - 28 u + 27 = 0 : u = 27, u = 1

u = 27, u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 27 : x = 3

Solve

3^{x} = 1 : x = 0

x = 3, x = 0

1808 = 60 t + 1800 e^{- \frac{t}{30}}

2^{x} = 61

e^{(x^{2} + 4 x - 2)} = 16

4^{- 4 x} = 25

5^{8} \cdot 5^{4} = (125)^{x}

What is the answer to 3^{2x}-28\times 3^x+27=0 ?
The answer to 3^{2x}-28\times 3^x+27=0 is x=3,x=0
Solve for x: 3^{2x}-28\times 3^x+27=0
The solution is x=3,x=0