What is the answer to log_{3}(27^{3x+4})=-2 ?

The answer to log_{3}(27^{3x+4})=-2 is x=-14/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(27^{3x+4})=-2

lo g_{3} (2 7^{3 x + 4}) = - 2

x = - \frac{14}{9}

Decimal Notation

x = - 1.55555 \dots

Solution steps

lo g_{3} (2 7^{3 x + 4}) = - 2

Rewrite the equation with

2 7^{3 x + 4} = u

lo g_{3} (u) = - 2

Solve

lo g_{3} (u) = - 2 : u = \frac{1}{9}

u = \frac{1}{9}

Substitute back

u = 2 7^{3 x + 4},

solve for

x

Solve

2 7^{3 x + 4} = \frac{1}{9} : x = - \frac{14}{9}

x = - \frac{14}{9}

9^{x} + 4 \cdot 3^{x} - 3 = 0

3^{2 x} = 6^{3 x - 1}

4^{5 x} = 7^{x + 3}

e^{2 x} + 3 e^{x} - 4 = 0

\frac{2 5 ^{x}}{5} = 1

What is the answer to log_{3}(27^{3x+4})=-2 ?
The answer to log_{3}(27^{3x+4})=-2 is x=-14/9
Solve for x: log_{3}(27^{3x+4})=-2
The solution is x=-14/9