What is the answer to 3^{2x}=6^{3x-1} ?

The answer to 3^{2x}=6^{3x-1} is x=(ln(6))/(ln(24))

Solve for x: 3^{2x}=6^{3x-1}

The solution is x=(ln(6))/(ln(24))

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3^{2 x} = 6^{3 x - 1}

x = \frac{ln ( 6 )}{ln ( 24 )}

Decimal Notation

x = 0.56379 \dots

Solution steps

3^{2 x} = 6^{3 x - 1}

Apply exponent rules

2 x ln (3) = (3 x - 1) ln (6)

Solve

2 x ln (3) = (3 x - 1) ln (6) : x = \frac{ln ( 6 )}{ln ( 24 )}

x = \frac{ln ( 6 )}{ln ( 24 )}

4^{5 x} = 7^{x + 3}

e^{2 x} + 3 e^{x} - 4 = 0

\frac{2 5 ^{x}}{5} = 1

\frac{2 5 ^{x}}{5 ^{x + 4}} = 2 5^{1 - x}

3^{2 x + 3} = 3

What is the answer to 3^{2x}=6^{3x-1} ?
The answer to 3^{2x}=6^{3x-1} is x=(ln(6))/(ln(24))
Solve for x: 3^{2x}=6^{3x-1}
The solution is x=(ln(6))/(ln(24))