What is the answer to 3^{(1-2x)}=4^x ?

The answer to 3^{(1-2x)}=4^x is x=(ln(3))/(2ln(6))

Solve for x: 3^{(1-2x)}=4^x

The solution is x=(ln(3))/(2ln(6))

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3^{(1 - 2 x)} = 4^{x}

x = \frac{ln ( 3 )}{2 ln ( 6 )}

Decimal Notation

x = 0.30657 \dots

Solution steps

3^{(1 - 2 x)} = 4^{x}

Apply exponent rules

(1 - 2 x) ln (3) = x ln (4)

Solve

(1 - 2 x) ln (3) = x ln (4) : x = \frac{ln ( 3 )}{2 ln ( 6 )}

x = \frac{ln ( 3 )}{2 ln ( 6 )}

2^{x + 3} + 2^{x + 2} = 48

2 5^{6 - 2 x} = 5

3^{x - 4} = 243

y, x = e^{- y}

What is the answer to 3^{(1-2x)}=4^x ?
The answer to 3^{(1-2x)}=4^x is x=(ln(3))/(2ln(6))
Solve for x: 3^{(1-2x)}=4^x
The solution is x=(ln(3))/(2ln(6))