What is the answer to 12^{x-1}=20^2 ?

The answer to 12^{x-1}=20^2 is x=(2ln(20))/(ln(12))+1

Solve for x: 12^{x-1}=20^2

The solution is x=(2ln(20))/(ln(12))+1

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1 2^{x - 1} = 2 0^{2}

x = \frac{2 ln ( 20 )}{ln ( 12 )} + 1

Decimal Notation

x = 3.41114 \dots

Solution steps

1 2^{x - 1} = 2 0^{2}

Apply exponent rules

(x - 1) ln (12) = 2 ln (20)

Solve

(x - 1) ln (12) = 2 ln (20) : x = \frac{2 ln ( 20 )}{ln ( 12 )} + 1

x = \frac{2 ln ( 20 )}{ln ( 12 )} + 1

2^{5 x + 1} = 4

8^{3 x - 1} = 6 4^{2 x}

2^{2 - x} = 9

100 = 1 0^{\frac{x}{10}}

e^{x + 1} = 3^{x + 3}

What is the answer to 12^{x-1}=20^2 ?
The answer to 12^{x-1}=20^2 is x=(2ln(20))/(ln(12))+1
Solve for x: 12^{x-1}=20^2
The solution is x=(2ln(20))/(ln(12))+1