What is the answer to 2^{2-x}=9 ?

The answer to 2^{2-x}=9 is x=-(2ln(3)-2ln(2))/(ln(2))

Solve for x: 2^{2-x}=9

The solution is x=-(2ln(3)-2ln(2))/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{2 - x} = 9

x = - \frac{2 ln ( 3 ) - 2 ln ( 2 )}{ln ( 2 )}

Decimal Notation

x = - 1.16992 \dots

Solution steps

2^{2 - x} = 9

Apply exponent rules

(2 - x) ln (2) = ln (9)

Solve

(2 - x) ln (2) = ln (9) : x = - \frac{2 ln ( 3 ) - 2 ln ( 2 )}{ln ( 2 )}

x = - \frac{2 ln ( 3 ) - 2 ln ( 2 )}{ln ( 2 )}

100 = 1 0^{\frac{x}{10}}

e^{x + 1} = 3^{x + 3}

3 6^{2 x - 3} = 6

e^{x + 1} = e^{x} + 7

5^{x + 1} - 5^{x - 2} = 620

What is the answer to 2^{2-x}=9 ?
The answer to 2^{2-x}=9 is x=-(2ln(3)-2ln(2))/(ln(2))
Solve for x: 2^{2-x}=9
The solution is x=-(2ln(3)-2ln(2))/(ln(2))