What is the answer to 3^{x+1}-4\times 3^{x-2}=69 ?

The answer to 3^{x+1}-4\times 3^{x-2}=69 is x=3

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3^{x+1}-4\times 3^{x-2}=69

3^{x + 1} - 4 \cdot 3^{x - 2} = 69

x = 3

Solution steps

3^{x + 1} - 4 \cdot 3^{x - 2} = 69

Factor

3^{x + 1} - 4 \cdot 3^{x - 2} : 23 \cdot 3^{x - 2}

23 \cdot 3^{x - 2} = 69

Divide both sides by

23

3^{x - 2} = 3

Apply exponent rules

x - 2 = 1

Solve

x - 2 = 1 : x = 3

x = 3

\frac{e ^{x} + 9}{e ^{- x} + 5} = 2

4 \cdot 2^{x} = 5

\frac{3 ^{x} + 3 ^{- x}}{3 ^{x} - 3 ^{- x}} = 20

4 \times e^{2.7 x} = 33

4^{x + 2} = 8

What is the answer to 3^{x+1}-4\times 3^{x-2}=69 ?
The answer to 3^{x+1}-4\times 3^{x-2}=69 is x=3
Solve for x: 3^{x+1}-4\times 3^{x-2}=69
The solution is x=3