What is the answer to 4*2^x=5 ?

The answer to 4*2^x=5 is x=(ln(5/4))/(ln(2))

The solution is x=(ln(5/4))/(ln(2))

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4*2^x=5

4 \cdot 2^{x} = 5

x = \frac{ln ( \frac{5}{4} )}{ln ( 2 )}

Decimal Notation

x = 0.32192 \dots

Solution steps

4 \cdot 2^{x} = 5

Divide both sides by

4

2^{x} = \frac{5}{4}

Apply exponent rules

x ln (2) = ln (\frac{5}{4})

Solve

x ln (2) = ln (\frac{5}{4}) : x = \frac{ln ( \frac{5}{4} )}{ln ( 2 )}

x = \frac{ln ( \frac{5}{4} )}{ln ( 2 )}

\frac{3 ^{x} + 3 ^{- x}}{3 ^{x} - 3 ^{- x}} = 20

4 \times e^{2.7 x} = 33

4^{x + 2} = 8

e^{2 x} - 8 e^{x} = 20

y, ln (x) + e^{- \frac{y}{x}} = c