What is the answer to solvefor y,ln(x)+e^{-y/x}=c ?

The answer to solvefor y,ln(x)+e^{-y/x}=c is y=-xln(c-ln(x))

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solvefor y,ln(x)+e^{-y/x}=c

solve for

y, ln (x) + e^{- \frac{y}{x}} = c

y = - x ln (c - ln (x))

Solution steps

ln (x) + e^{- \frac{y}{x}} = c

Move

ln (x)

to the right side

e^{- \frac{y}{x}} = c - ln (x)

Apply exponent rules

- \frac{y}{x} = ln (c - ln (x))

Solve

- \frac{y}{x} = ln (c - ln (x)) : y = - x ln (c - ln (x))

y = - x ln (c - ln (x))

3^{x + 1} + 3^{x - 1} = 30

2 e^{8 x} + e^{4 x} - 1 = 0

125 = 5^{x}

1 0^{2 x + 9} = 6 \cdot 7^{x - 4}

y, x = 4 - 3^{2 y - 1}

What is the answer to solvefor y,ln(x)+e^{-y/x}=c ?
The answer to solvefor y,ln(x)+e^{-y/x}=c is y=-xln(c-ln(x))