What is the answer to 5^x=37 ?

The answer to 5^x=37 is x=(ln(37))/(ln(5))

The solution is x=(ln(37))/(ln(5))

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5^x=37

5^{x} = 37

x = \frac{ln ( 37 )}{ln ( 5 )}

Decimal Notation

x = 2.24358 \dots

Solution steps

5^{x} = 37

Apply exponent rules

x ln (5) = ln (37)

Solve

x ln (5) = ln (37) : x = \frac{ln ( 37 )}{ln ( 5 )}

x = \frac{ln ( 37 )}{ln ( 5 )}

6^{x + 1} = 7^{6 x - 1}

- 1 (1 - 2^{x}) = 2094

4^{x} \cdot 3^{2 x} = 6

e^{x^{2}} = e^{7 x - 12}

100 = 65 + 145 e^{- 0.05 \times x}