What is the answer to 2^{3x-1}=2*3^{2-3x} ?

The answer to 2^{3x-1}=2*3^{2-3x} is x= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{3x-1}=2*3^{2-3x}

2^{3 x - 1} = 2 \cdot 3^{2 - 3 x}

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

2^{3 x - 1} = 2 \cdot 3^{2 - 3 x}

Apply exponent rules

(3 x - 1) ln (2) = ln (2) + (2 - 3 x) ln (3)

Solve

(3 x - 1) ln (2) = ln (2) + (2 - 3 x) ln (3) : x = \frac{2}{3}

x = \frac{2}{3}

6 e^{1 - x} = 25

x, 2^{x + 1} = \frac{1}{2 ^{2 x + 3}}

3 2^{x} = (\frac{1}{128})^{x - 4}

4^{x + 1} + 4^{x + 2} - 320 = 0

a x \cdot e^{b x}

What is the answer to 2^{3x-1}=2*3^{2-3x} ?
The answer to 2^{3x-1}=2*3^{2-3x} is x= 2/3
Solve for x: 2^{3x-1}=2*3^{2-3x}
The solution is x= 2/3