What is the answer to 32^x=(1/128)^{x-4} ?

The answer to 32^x=(1/128)^{x-4} is x= 7/3

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32^x=(1/128)^{x-4}

3 2^{x} = (\frac{1}{128})^{x - 4}

x = \frac{7}{3}

Decimal Notation

x = 2.33333 \dots

Solution steps

3 2^{x} = (\frac{1}{128})^{x - 4}

Apply exponent rules

5 x = - 7 (x - 4)

Solve

5 x = - 7 (x - 4) : x = \frac{7}{3}

x = \frac{7}{3}

4^{x + 1} + 4^{x + 2} - 320 = 0

a x \cdot e^{b x}

e^{4 x - 4} = 9

1 0^{2 x} = 2

x \cdot e^{x} = 0

What is the answer to 32^x=(1/128)^{x-4} ?
The answer to 32^x=(1/128)^{x-4} is x= 7/3
Solve for x: 32^x=(1/128)^{x-4}
The solution is x= 7/3