What is the answer to 27^{3x+5}=81^{4x+1} ?

The answer to 27^{3x+5}=81^{4x+1} is x= 11/7

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27^{3x+5}=81^{4x+1}

2 7^{3 x + 5} = 8 1^{4 x + 1}

x = \frac{11}{7}

Decimal Notation

x = 1.57142 \dots

Solution steps

2 7^{3 x + 5} = 8 1^{4 x + 1}

Apply exponent rules

3 (3 x + 5) = 4 (4 x + 1)

Solve

3 (3 x + 5) = 4 (4 x + 1) : x = \frac{11}{7}

x = \frac{11}{7}

4 = 102 4^{x}

0.2 5^{2 x - 1} = 8^{x + 3}

86 \cdot 1 0^{\frac{x}{4}} = 89

3^{4 x - 7} = \frac{3 ^{2 x}}{3}

y, x = e^{7 y}

What is the answer to 27^{3x+5}=81^{4x+1} ?
The answer to 27^{3x+5}=81^{4x+1} is x= 11/7
Solve for x: 27^{3x+5}=81^{4x+1}
The solution is x= 11/7