What is the answer to 9*2^{2x}=64 ?

The answer to 9*2^{2x}=64 is x=(ln(64/9))/(2ln(2))

Solve for x: 9*2^{2x}=64

The solution is x=(ln(64/9))/(2ln(2))

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9 \cdot 2^{2 x} = 64

x = \frac{ln ( \frac{64}{9} )}{2 ln ( 2 )}

Decimal Notation

x = 1.41503 \dots

Solution steps

9 \cdot 2^{2 x} = 64

Divide both sides by

9

2^{2 x} = \frac{64}{9}

Apply exponent rules

2 x ln (2) = ln (\frac{64}{9})

Solve

2 x ln (2) = ln (\frac{64}{9}) : x = \frac{ln ( \frac{64}{9} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{64}{9} )}{2 ln ( 2 )}

x, P a^{x} = Q b^{x}

1 2^{x} = 14 4^{x - 3}

7^{3 x - 1} = 4 9^{x + 1}

x, e^{x} = - \frac{1}{2}

81 = 2 7^{x + 2}

What is the answer to 9*2^{2x}=64 ?
The answer to 9*2^{2x}=64 is x=(ln(64/9))/(2ln(2))
Solve for x: 9*2^{2x}=64
The solution is x=(ln(64/9))/(2ln(2))