What is the answer to sqrt(16^{2x-2)}=2^{3x+3} ?

The answer to sqrt(16^{2x-2)}=2^{3x+3} is x=7

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sqrt(16^{2x-2)}=2^{3x+3}

1 6^{2 x - 2} = 2^{3 x + 3}

x = 7

Solution steps

1 6^{2 x - 2} = 2^{3 x + 3}

Apply exponent rules

2 (2 x - 2) = 3 x + 3

Solve

2 (2 x - 2) = 3 x + 3 : x = 7

x = 7

(2 \times (- 5))^{x^{2} - 5 x + 4} = 1

x^{x} = 6

3^{3 x + 5} = 3 \cdot 9^{x + 3}

9^{x} - 10 \times 3^{x} + 9 = 0

5^{a + 2} = \frac{1}{125}

What is the answer to sqrt(16^{2x-2)}=2^{3x+3} ?
The answer to sqrt(16^{2x-2)}=2^{3x+3} is x=7
Solve for x: sqrt(16^{2x-2)}=2^{3x+3}
The solution is x=7