What is the answer to 5^{x+1}=4^{2x-3} ?

The answer to 5^{x+1}=4^{2x-3} is x=(ln(320))/(4ln(2)-ln(5))

Solve for x: 5^{x+1}=4^{2x-3}

The solution is x=(ln(320))/(4ln(2)-ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{x + 1} = 4^{2 x - 3}

x = \frac{ln ( 320 )}{4 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = 4.95922 \dots

Solution steps

5^{x + 1} = 4^{2 x - 3}

Apply exponent rules

(x + 1) ln (5) = (2 x - 3) ln (4)

Solve

(x + 1) ln (5) = (2 x - 3) ln (4) : x = \frac{ln ( 320 )}{4 ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 320 )}{4 ln ( 2 ) - ln ( 5 )}

1 6^{- x + 2} = 8

15 x^{2} e^{- x} - 5 x^{3} e^{- x} = 0

e^{k x} = 0.5

8^{2 x + 1} = 105

\frac{1 0 ^{3 x}}{1 0 ^{x}} = 30

What is the answer to 5^{x+1}=4^{2x-3} ?
The answer to 5^{x+1}=4^{2x-3} is x=(ln(320))/(4ln(2)-ln(5))
Solve for x: 5^{x+1}=4^{2x-3}
The solution is x=(ln(320))/(4ln(2)-ln(5))