What is the answer to 9*2^{4x}=1 ?

The answer to 9*2^{4x}=1 is x=-(ln(3))/(2ln(2))

Solve for x: 9*2^{4x}=1

The solution is x=-(ln(3))/(2ln(2))

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9 \cdot 2^{4 x} = 1

x = - \frac{ln ( 3 )}{2 ln ( 2 )}

Decimal Notation

x = - 0.79248 \dots

Solution steps

9 \cdot 2^{4 x} = 1

Divide both sides by

9

2^{4 x} = \frac{1}{9}

Apply exponent rules

4 x ln (2) = ln (\frac{1}{9})

Solve

4 x ln (2) = ln (\frac{1}{9}) : x = - \frac{ln ( 3 )}{2 ln ( 2 )}

x = - \frac{ln ( 3 )}{2 ln ( 2 )}

6 e^{6 x} - e^{- x} = 0

7^{3 x - 1} = 49

3 e^{- x} = 0

2. 5^{x} = 0.0087

3^{x - 1} + 3^{x} + 3^{x + 1} = 13

What is the answer to 9*2^{4x}=1 ?
The answer to 9*2^{4x}=1 is x=-(ln(3))/(2ln(2))
Solve for x: 9*2^{4x}=1
The solution is x=-(ln(3))/(2ln(2))