What is the answer to 3^{x-1}+3^x+3^{x+1}=13 ?

The answer to 3^{x-1}+3^x+3^{x+1}=13 is x=1

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3^{x-1}+3^x+3^{x+1}=13

3^{x - 1} + 3^{x} + 3^{x + 1} = 13

x = 1

Solution steps

3^{x - 1} + 3^{x} + 3^{x + 1} = 13

Factor

3^{x - 1} + 3^{x} + 3^{x + 1} : 13 \cdot 3^{x - 1}

13 \cdot 3^{x - 1} = 13

Divide both sides by

13

3^{x - 1} = 1

Apply exponent rules

(x - 1) ln (3) = ln (1)

Solve

(x - 1) ln (3) = ln (1) : x = 1

x = 1

5000 = 2750 e^{(0.08 t)}

9^{x + 2} = 3^{x + 1}

(\frac{2}{3})^{x} \times (\frac{9}{8})^{x} = \frac{27}{64}

3^{2 x} + 2 \cdot 3^{(x + 1)} = 16

n, y^{n} + 4 y = 0

What is the answer to 3^{x-1}+3^x+3^{x+1}=13 ?
The answer to 3^{x-1}+3^x+3^{x+1}=13 is x=1
Solve for x: 3^{x-1}+3^x+3^{x+1}=13
The solution is x=1