What are the solutions to the equation 4r-3=3(3r^4) ?

The solutions to the equation 4r-3=3(3r^4) are No Solution for r\in\mathbb{R}

Find the zeros of 4r-3=3(3r^4)

The zeros of 4r-3=3(3r^4) are No Solution for r\in\mathbb{R}

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4 r - 3 = 3 (3 r^{4})

No Solution for r \in R

Solution steps

4 r - 3 = 3 (3 r^{4})

Expand

3 (3 r^{4}) : 9 r^{4}

4 r - 3 = 9 r^{4}

Switch sides

9 r^{4} = 4 r - 3

Move

3

to the left side

9 r^{4} + 3 = 4 r

Move

4 r

to the left side

9 r^{4} + 3 - 4 r = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

9 r^{4} - 4 r + 3 = 0

Find one solution for

9 r^{4} - 4 r + 3 = 0

using Newton-Raphson:

No Solution for

r \in R

The solution is

No Solution for r \in R

3 x^{3} + 4 x^{2} + 4 x + 9 = 9

x^{5} = 5 x^{3}

6 y^{5} - 8 y^{3} - 2 y + 1 = 0

(x^{2} + 3)^{3} = 0

x^{5} - 10 x^{3} + 36 x = 0

What are the solutions to the equation 4r-3=3(3r^4) ?
The solutions to the equation 4r-3=3(3r^4) are No Solution for r\in\mathbb{R}
Find the zeros of 4r-3=3(3r^4)
The zeros of 4r-3=3(3r^4) are No Solution for r\in\mathbb{R}