What are the solutions to the equation (x^2-4)^3=0 ?

The solutions to the equation (x^2-4)^3=0 are x=2,x=-2

Find the zeros of (x^2-4)^3=0

The zeros of (x^2-4)^3=0 are x=2,x=-2

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(x^{2} - 4)^{3} = 0

x = 2, x = - 2

Solution steps

(x^{2} - 4)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} - 4 = 0 : x = 2, x = - 2

The solutions are

x = 2, x = - 2

4 y^{4} - 4 y = 0

4 x^{3} + 2 x - 8 = 0

4 π x^{2} = \frac{4 π x ^{3}}{3}

9 x^{5} - 72 x^{2} = 0

6 = 1 - 2 n^{5}

What are the solutions to the equation (x^2-4)^3=0 ?
The solutions to the equation (x^2-4)^3=0 are x=2,x=-2
Find the zeros of (x^2-4)^3=0
The zeros of (x^2-4)^3=0 are x=2,x=-2