What are the solutions to the equation roots s^3+5s^2+24s+20 ?

The solutions to the equation roots s^3+5s^2+24s+20 are s=-1,s=-2+4i,s=-2-4i

Find the zeros of roots s^3+5s^2+24s+20

The zeros of roots s^3+5s^2+24s+20 are s=-1,s=-2+4i,s=-2-4i

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roots

s^{3} + 5 s^{2} + 24 s + 20

s = - 1, s = - 2 + 4 i, s = - 2 - 4 i

Solution steps

s^{3} + 5 s^{2} + 24 s + 20

The roots are the intercepts with the x-axis

(y = 0)

s^{3} + 5 s^{2} + 24 s + 20 = 0

Factor

s^{3} + 5 s^{2} + 24 s + 20 : (s + 1) (s^{2} + 4 s + 20)

(s + 1) (s^{2} + 4 s + 20) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s + 1 = 0 or s^{2} + 4 s + 20 = 0

Solve

s + 1 = 0 : s = - 1

Solve

s^{2} + 4 s + 20 = 0 : s = - 2 + 4 i, s = - 2 - 4 i

The solutions are

s = - 1, s = - 2 + 4 i, s = - 2 - 4 i

\frac{4 x}{3} x^{8} = 20

x^{4} - 4 x^{2} - 45 = 0

x^{4} - 2 x^{3} - 5 x^{2} + 8 x + 4 = 0

3 x^{3} + 81 = 0

16 x^{3} = 54

What are the solutions to the equation roots s^3+5s^2+24s+20 ?
The solutions to the equation roots s^3+5s^2+24s+20 are s=-1,s=-2+4i,s=-2-4i
Find the zeros of roots s^3+5s^2+24s+20
The zeros of roots s^3+5s^2+24s+20 are s=-1,s=-2+4i,s=-2-4i