What are the solutions to the equation 1/4 x^3+x-1=3 ?

The solutions to the equation 1/4 x^3+x-1=3 are x=2,x=-1+sqrt(7)i,x=-1-sqrt(7)i

Find the zeros of 1/4 x^3+x-1=3

The zeros of 1/4 x^3+x-1=3 are x=2,x=-1+sqrt(7)i,x=-1-sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{4} x^{3} + x - 1 = 3

x = 2, x = - 1 + 7 i, x = - 1 - 7 i

Solution steps

\frac{1}{4} x^{3} + x - 1 = 3

Multiply both sides by

4

x^{3} + 4 x - 4 = 12

Move

12

to the left side

x^{3} + 4 x - 16 = 0

Factor

x^{3} + 4 x - 16 : (x - 2) (x^{2} + 2 x + 8)

(x - 2) (x^{2} + 2 x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 2 x + 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 8 = 0 : x = - 1 + 7 i, x = - 1 - 7 i

The solutions are

x = 2, x = - 1 + 7 i, x = - 1 - 7 i

1.1712 x^{6} - 4.1862 x + 3.0151 = 0

2 x^{3} - 3 x^{2} + 18 x - 27 = 0

x^{2} x + 5 a = 30

0.3 x^{9} - 2.4 = 0

4 x^{3} - 21 x^{2} = 0

What are the solutions to the equation 1/4 x^3+x-1=3 ?
The solutions to the equation 1/4 x^3+x-1=3 are x=2,x=-1+sqrt(7)i,x=-1-sqrt(7)i
Find the zeros of 1/4 x^3+x-1=3
The zeros of 1/4 x^3+x-1=3 are x=2,x=-1+sqrt(7)i,x=-1-sqrt(7)i