What are the solutions to the equation roots x^3-8x^2+25x-26 ?

The solutions to the equation roots x^3-8x^2+25x-26 are x=2,x=3+2i,x=3-2i

Find the zeros of roots x^3-8x^2+25x-26

The zeros of roots x^3-8x^2+25x-26 are x=2,x=3+2i,x=3-2i

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roots

x^{3} - 8 x^{2} + 25 x - 26

x = 2, x = 3 + 2 i, x = 3 - 2 i

Solution steps

x^{3} - 8 x^{2} + 25 x - 26

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 8 x^{2} + 25 x - 26 = 0

Factor

x^{3} - 8 x^{2} + 25 x - 26 : (x - 2) (x^{2} - 6 x + 13)

(x - 2) (x^{2} - 6 x + 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - 6 x + 13 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 6 x + 13 = 0 : x = 3 + 2 i, x = 3 - 2 i

The solutions are

x = 2, x = 3 + 2 i, x = 3 - 2 i

4 x^{3} - 6 x + 4 = 0

4 r^{3} + 5 r^{2} = 0

x^{5} + 2 x^{3} + x = 0

x^{3} + 7 x^{2} - 9 x - 63 = 0

125 t^{10} - 2 t^{7} = 0

What are the solutions to the equation roots x^3-8x^2+25x-26 ?
The solutions to the equation roots x^3-8x^2+25x-26 are x=2,x=3+2i,x=3-2i
Find the zeros of roots x^3-8x^2+25x-26
The zeros of roots x^3-8x^2+25x-26 are x=2,x=3+2i,x=3-2i