What are the solutions to the equation 12x^3-91x^2+50x-7=0 ?

The solutions to the equation 12x^3-91x^2+50x-7=0 are x=7,x= 1/4 ,x= 1/3

Find the zeros of 12x^3-91x^2+50x-7=0

The zeros of 12x^3-91x^2+50x-7=0 are x=7,x= 1/4 ,x= 1/3

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12 x^{3} - 91 x^{2} + 50 x - 7 = 0

x = 7, x = \frac{1}{4}, x = \frac{1}{3}

Decimal Notation

x = 7, x = 0.25, x = 0.33333 \dots

Solution steps

12 x^{3} - 91 x^{2} + 50 x - 7 = 0

Factor

12 x^{3} - 91 x^{2} + 50 x - 7 : (x - 7) (4 x - 1) (3 x - 1)

(x - 7) (4 x - 1) (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 7 = 0 or 4 x - 1 = 0 or 3 x - 1 = 0

Solve

x - 7 = 0 : x = 7

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions are

x = 7, x = \frac{1}{4}, x = \frac{1}{3}

4 x^{3} + 25 x = 46 x - 10

5 x^{3} - 12 x^{2} + 19 x - 6 = 0

x^{3} + 3 x^{2} - 4 x - 12

a x^{3}

m^{3} - 3 m^{2} + 2 m - 6 = 0

What are the solutions to the equation 12x^3-91x^2+50x-7=0 ?
The solutions to the equation 12x^3-91x^2+50x-7=0 are x=7,x= 1/4 ,x= 1/3
Find the zeros of 12x^3-91x^2+50x-7=0
The zeros of 12x^3-91x^2+50x-7=0 are x=7,x= 1/4 ,x= 1/3