What are the solutions to the equation m^3-3m^2+2m-6=0 ?

The solutions to the equation m^3-3m^2+2m-6=0 are m=3,m=sqrt(2)i,m=-sqrt(2)i

Find the zeros of m^3-3m^2+2m-6=0

The zeros of m^3-3m^2+2m-6=0 are m=3,m=sqrt(2)i,m=-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{3} - 3 m^{2} + 2 m - 6 = 0

m = 3, m = 2 i, m = - 2 i

Solution steps

m^{3} - 3 m^{2} + 2 m - 6 = 0

Factor

m^{3} - 3 m^{2} + 2 m - 6 : (m - 3) (m^{2} + 2)

(m - 3) (m^{2} + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m - 3 = 0 or m^{2} + 2 = 0

Solve

m - 3 = 0 : m = 3

Solve

m^{2} + 2 = 0 : m = 2 i, m = - 2 i

The solutions are

m = 3, m = 2 i, m = - 2 i

x^{4} + 2 x^{3} = 5 x^{2} + 6 x

7 x^{3} = 189

x^{3} - 4 x^{2} + x + 6

m^{3} - 6 m^{2} = 0

x^{3} - 9 x^{2} + 24 x - 20 = 0

What are the solutions to the equation m^3-3m^2+2m-6=0 ?
The solutions to the equation m^3-3m^2+2m-6=0 are m=3,m=sqrt(2)i,m=-sqrt(2)i
Find the zeros of m^3-3m^2+2m-6=0
The zeros of m^3-3m^2+2m-6=0 are m=3,m=sqrt(2)i,m=-sqrt(2)i