What are the solutions to the equation t^3=27 ?

The solutions to the equation t^3=27 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i

Find the zeros of t^3=27

The zeros of t^3=27 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i

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t^{3} = 27

t = 3, t = - \frac{3}{2} + \frac{3 3}{2} i, t = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

t^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

t = 3, t = - \frac{3}{2} + \frac{3 3}{2} i, t = - \frac{3}{2} - \frac{3 3}{2} i

2 π x^{2} (\frac{9 - x}{3}) - 30 = 0

4 x^{3} + 3 x^{2} = 0

25 x^{3} - x = 0

3 x^{4} + 10 x^{2} - 8 = 0

2 x^{4} - 30 x^{2} - 2 x = 0

What are the solutions to the equation t^3=27 ?
The solutions to the equation t^3=27 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i
Find the zeros of t^3=27
The zeros of t^3=27 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i