What are the solutions to the equation (x^2+4)^3=0 ?

The solutions to the equation (x^2+4)^3=0 are x=2i,x=-2i

Find the zeros of (x^2+4)^3=0

The zeros of (x^2+4)^3=0 are x=2i,x=-2i

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(x^{2} + 4)^{3} = 0

x = 2 i, x = - 2 i

Solution steps

(x^{2} + 4)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = 2 i, x = - 2 i

26 = 16 \cdot (1 + x)^{4}

x^{6} - 2 x^{3} + 2

4 x^{3} + 6 x^{2} - 8 x + 1 = 0

x^{4} + x^{3} - 3 x^{2} - 5 x - 2 = 0

m^{4} - 625 = 0

What are the solutions to the equation (x^2+4)^3=0 ?
The solutions to the equation (x^2+4)^3=0 are x=2i,x=-2i
Find the zeros of (x^2+4)^3=0
The zeros of (x^2+4)^3=0 are x=2i,x=-2i