What are the solutions to the equation -x^3+27x-54=0 ?

The solutions to the equation -x^3+27x-54=0 are x=3,x=-6

Find the zeros of -x^3+27x-54=0

The zeros of -x^3+27x-54=0 are x=3,x=-6

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- x^{3} + 27 x - 54 = 0

x = 3, x = - 6

Solution steps

- x^{3} + 27 x - 54 = 0

Factor

- x^{3} + 27 x - 54 : - (x - 3)^{2} (x + 6)

- (x - 3)^{2} (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 6 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 3, x = - 6

(x + 3)^{4} = 16

x^{4} - 5 x^{2} + 4

x^{4} - 2 x^{3} + 6 x^{2} - 18 x - 27 = 0

r^{3} + r^{2} - r - 1 = 0

x^{4} - x^{2} + \frac{1}{4} = 0

What are the solutions to the equation -x^3+27x-54=0 ?
The solutions to the equation -x^3+27x-54=0 are x=3,x=-6
Find the zeros of -x^3+27x-54=0
The zeros of -x^3+27x-54=0 are x=3,x=-6