What are the solutions to the equation s^3+5s^2+24s+20=0 ?

The solutions to the equation s^3+5s^2+24s+20=0 are s=-1,s=-2+4i,s=-2-4i

Find the zeros of s^3+5s^2+24s+20=0

The zeros of s^3+5s^2+24s+20=0 are s=-1,s=-2+4i,s=-2-4i

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s^{3} + 5 s^{2} + 24 s + 20 = 0

s = - 1, s = - 2 + 4 i, s = - 2 - 4 i

Solution steps

s^{3} + 5 s^{2} + 24 s + 20 = 0

Factor

s^{3} + 5 s^{2} + 24 s + 20 : (s + 1) (s^{2} + 4 s + 20)

(s + 1) (s^{2} + 4 s + 20) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s + 1 = 0 or s^{2} + 4 s + 20 = 0

Solve

s + 1 = 0 : s = - 1

Solve

s^{2} + 4 s + 20 = 0 : s = - 2 + 4 i, s = - 2 - 4 i

The solutions are

s = - 1, s = - 2 + 4 i, s = - 2 - 4 i

x^{3} - 5 x^{2} - 25 x + 125 = 0

x^{3} = (- 1 - 3 i)

7 \times x - 9 = 4 \times x^{27}

t^{4} - 3 t^{3} - 40 t^{2} = 0

y, 2 x^{3} - 3 y^{2} = 8

What are the solutions to the equation s^3+5s^2+24s+20=0 ?
The solutions to the equation s^3+5s^2+24s+20=0 are s=-1,s=-2+4i,s=-2-4i
Find the zeros of s^3+5s^2+24s+20=0
The zeros of s^3+5s^2+24s+20=0 are s=-1,s=-2+4i,s=-2-4i