What are the solutions to the equation 4x^3-51x^2+210x-275=0 ?

The solutions to the equation 4x^3-51x^2+210x-275=0 are x=5,x= 11/4

Find the zeros of 4x^3-51x^2+210x-275=0

The zeros of 4x^3-51x^2+210x-275=0 are x=5,x= 11/4

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4 x^{3} - 51 x^{2} + 210 x - 275 = 0

x = 5, x = \frac{11}{4}

Decimal Notation

x = 5, x = 2.75

Solution steps

4 x^{3} - 51 x^{2} + 210 x - 275 = 0

Factor

4 x^{3} - 51 x^{2} + 210 x - 275 : (x - 5)^{2} (4 x - 11)

(x - 5)^{2} (4 x - 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or 4 x - 11 = 0

Solve

x - 5 = 0 : x = 5

Solve

4 x - 11 = 0 : x = \frac{11}{4}

The solutions are

x = 5, x = \frac{11}{4}

x^{4} - 4 x^{3} + 10 x^{2} - 12 x + 5 = 0

x^{3} + x^{2} - 56 x + 144 = 0

x^{4} - 5 x^{3} - 6 x^{2} + 7 x - 2 = 0

2 x^{3} - 3 x^{2} + 2 = 0

x^{3} + 8 x^{2} + 37 x + 50

What are the solutions to the equation 4x^3-51x^2+210x-275=0 ?
The solutions to the equation 4x^3-51x^2+210x-275=0 are x=5,x= 11/4
Find the zeros of 4x^3-51x^2+210x-275=0
The zeros of 4x^3-51x^2+210x-275=0 are x=5,x= 11/4