What are the solutions to the equation 20x^3+12x^2-5x-3=0 ?

The solutions to the equation 20x^3+12x^2-5x-3=0 are x=-3/5 ,x=-1/2 ,x= 1/2

Find the zeros of 20x^3+12x^2-5x-3=0

The zeros of 20x^3+12x^2-5x-3=0 are x=-3/5 ,x=-1/2 ,x= 1/2

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20 x^{3} + 12 x^{2} - 5 x - 3 = 0

x = - \frac{3}{5}, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = - 0.6, x = - 0.5, x = 0.5

Solution steps

20 x^{3} + 12 x^{2} - 5 x - 3 = 0

Factor

20 x^{3} + 12 x^{2} - 5 x - 3 : (5 x + 3) (2 x + 1) (2 x - 1)

(5 x + 3) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 3 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

5 x + 3 = 0 : x = - \frac{3}{5}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = - \frac{3}{5}, x = - \frac{1}{2}, x = \frac{1}{2}

x^{4} - 10 x^{3} + 120 x + 144 = 0

x^{3} - 3 x^{2} + 4 x - 4

x^{3} - x^{2} - x - 15 = 0

x^{3} + 8 x^{2} + 9 x - 18

x^{4} - 9 x^{2} - 400 = 0

What are the solutions to the equation 20x^3+12x^2-5x-3=0 ?
The solutions to the equation 20x^3+12x^2-5x-3=0 are x=-3/5 ,x=-1/2 ,x= 1/2
Find the zeros of 20x^3+12x^2-5x-3=0
The zeros of 20x^3+12x^2-5x-3=0 are x=-3/5 ,x=-1/2 ,x= 1/2