What are the solutions to the equation roots x^3-3x^2+4x-4 ?

The solutions to the equation roots x^3-3x^2+4x-4 are x=2,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

Find the zeros of roots x^3-3x^2+4x-4

The zeros of roots x^3-3x^2+4x-4 are x=2,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{3} - 3 x^{2} + 4 x - 4

x = 2, x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

Solution steps

x^{3} - 3 x^{2} + 4 x - 4

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 3 x^{2} + 4 x - 4 = 0

Factor

x^{3} - 3 x^{2} + 4 x - 4 : (x - 2) (x^{2} - x + 2)

(x - 2) (x^{2} - x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - x + 2 = 0 : x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

The solutions are

x = 2, x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

x^{3} - x^{2} - x - 15 = 0

x^{3} + 8 x^{2} + 9 x - 18

x^{4} - 9 x^{2} - 400 = 0

x^{3} + 3 x^{2} + 3 x + 1 = 0

x^{4} - 2 x^{2} - 2 = 0

What are the solutions to the equation roots x^3-3x^2+4x-4 ?
The solutions to the equation roots x^3-3x^2+4x-4 are x=2,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2
Find the zeros of roots x^3-3x^2+4x-4
The zeros of roots x^3-3x^2+4x-4 are x=2,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2